In Boolean algebra \(\overline {A + B} =\)?
![In Boolean algebra \(\overline {A + B} =\)?](/img/relate-questions.png)
| In Boolean algebra \(\overline {A + B} =\) ?
A. <span class="math-tex">\(\bar A + \bar B\)</span>
B. <span class="math-tex">\(\bar A.\bar B\)</span>
C. <span class="math-tex">\(A + \bar B\)</span>
D. B + A
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Right Answer is: B
SOLUTION
According to De Morgan's law:
\(\overline {A + B} = \bar A.\bar B\)
\(\overline {A.B} = \bar A + \bar B\)
De Morgan's law helps in the simplification of Boolean algebra.